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## Important of Maths Formulas for Class 7

Here, we will provide the chapter-wise marks in exams for class 7th from NCERT books that will help you to understand the strategy where you should spend more time and how to prepare for the exams. Students generally face problems in understanding difficult math problems, so they should learn formulas and solutions wisely.

 Positive  + Positive = Positive Positive X Positive = Positive Negative + Negative = Negative Negative X Negative = Positive *Positive + Negative  or *Negative + Positive Negative X Positive = Negative * Subtract the smaller number from the larger number, then use the sign of the larger number in the answer. Positive X Negative = Negative Negative – Positive = Negative Positive ÷ Positive = Positive Positive – Negative = Positive Negative ÷ Negative = Positive *Negative – Negative = Negative + Positive Negative ÷ Positive = Negative Subtract the smaller number from the larger number, then use the sign of the larger number in the answer. Positive ÷ Negative = Negative

 Property Operations on integers Name Addition Subtraction Multiplication Division Closure a + b ∈ Z a – b ∈ Z a x b ∈ Z a / b ∉ Z Commutative a + b = b + a a – b ≠ b – a a x b = b x a a / b ≠ b / a Associative (a + b) + c = a + (b + c) (a – b) – c ≠ a – (b – c) (a x b) x c = a x (b x c) (a / b) / c ≠ a / (b / c) Distributive a x (b + c) = ab + ac a x (b – c) = ab – ac Not Applicable Not Applicable
 Proper fraction = $\ \frac{p}{q}$ Where, p > q Improper fraction = $\ \frac{p}{q}$ where, p < q Mixed fraction = $\ a \frac{p}{q}$ natural number and proper fraction Like fractions = $\ \frac{1}{2}, \frac{3}{2}, \frac{5}{2}, \frac{7}{2}, \frac{9}{2}$ Same denominator Unlike fractions = $\ \frac{1}{2}, \frac{3}{4}, \frac{5}{3}, \frac{7}{4}, \frac{9}{5}$ Different denominator Product of two fractions = $\ \frac{a}{b} \times \frac{p}{q} = \frac{ap}{bq}$ Reciprocal fractions = $\ \frac{p}{q} = \frac{q}{p}$ Addition of fractions = $\ \frac{a}{b} + \frac{p}{q} = \frac{qa+bp}{bq}$ Subtraction of fractions = $\ \frac{a}{b} – \frac{p}{q} = \frac{qa-bp}{bq}$ Multiplication of fractions = $\ \frac{a}{b} \times \frac{p}{q} = \frac{ap}{bq}$ Division of fractions = $\ \frac{\frac{a}{b}}{\frac{p}{q}} = \frac{aq}{bp}$
 Arithmetic Mean $\ \frac{Sum of Observation}{Number of Observation}$ Range Largest Observation – Smallest Observation Mode Large Number of Observations Median $\ (\frac{n + 1}{2})^{th} Obserbation$ Probability $\ \frac{No. of Favorable outcome}{No. of all possible outcome}$ Two complementary angles Measures add up to 90° Two supplementary angles Measures add up to 180° Two adjacent angles Have a common vertex and a common arm but no common interior. Linear pair Adjacent and supplementary
 Sides AB, BC, CA Angles ∠BAC, ∠ABC, ∠BCA Vertices A, B, C Pythagoras property (QR)2=(PQ)2+(PR)2 Angle sum property of triangle ∠A + ∠B + ∠C = 180∘ Equilateral triangles All sides are equal Isosceles triangle Two sides are equal
 Congruent Triangles Their corresponding parts are equal SSS Congruence of two triangles Three corresponding sides are equal SAS Congruence of two triangles Two corresponding sides and an angle are equal ASA Congruence of two triangles Two corresponding angles and a side are equal
 Simple Interest = $\ \frac{P×R×T} {100}$ Where, P=Principal, T= Time in years, R=Rate of interest per annum Rate = $\ \frac{SI \times 100} {P \times T}$ Principal = $\ \frac{SI \times 100} {R \times T}$ Time  = $\ \frac{SI \times 100} {R \times P}$ Discount = $\ MP – SP$ Principal= $\ Amount – Simpple\; Intrest$
 Perimeter of a Square = $\ 4 \times side$ Perimeter of a Rectangle = $\ 2 (Length + Breadth)$ Area of a Square = $\ Side^{2}$ Area of a Rectangle = $\ Length \times Breadth$ Area of a Parallelogram = $\ Base \times Height$ Area of a Triangle = $\ \frac{1}{2} (Base \times Height)$ Area of a Circle = $\ \pi r^{2}$
• (a + b)2=a2 + 2ab + b2
• (a−b)2=a2−2ab + b2
• (a + b)(a – b)=a2 – b2
• (x + a)(x + b)=x2 + (a + b)x + ab
• (x + a)(x – b)=x2 + (a – b)x – ab
• (x – a)(x + b)=x2 + (b – a)x – ab
• (x – a)(x – b)=x2 – (a + b)x + ab
• (a + b)3=a3 + b3 + 3ab(a + b)
• (a – b)3=a3 – b3 – 3ab(a – b)
• (am)(an) = am+n
• (ab)m = ambm
• (am)n = amn
• a0 = 1
• (-1)Even Number = 1
• (-1)Odd Number = -1

When followed right tricks and the strategy, this is possible to score well for students. Spend some time in understanding topics to know the Math syllabus and which topics should be given more time when compared to others.

### Chapter-wise Marks in Exam

So, how to start the preparation? All you have to do is to choose a topic and explore the list of formulas associated with that particular topic. The same strategy should be followed for all your subjects like Maths, chemistry, or Physics etc. Every time you want to calculate the percentage, area, perimeter for any figure then choose the formula and start your work right away. With this technique, you can always solve the most complex maths problems too at your convenience.

The next perfect solution is to check for Math Formulas online where you can download all formulas together in one shot. This technique is not only suitable for the students but for parents or teachers as well where you can find all the educational formulas together. Here, we have given quick chapter-wise marks in exams for class 7th.

 # Chapter Name Total Marks 1 Integers 14 2 Fractions and Decimals 17 3 Data Handling 14 4 Simple Equations 14 5 Line & Angles 12 6 Symmetry 9 Total 80

### NCERT Solutions Class 7 Maths By Chapters

If you refer NCERT solutions for class 7th then try to solve each problem wisely. Here, you will find problems related to each concept like integers, Decimals, Fractions, Equations, Data handling, angles, lines, triangles, rational numbers, congruence, algebraic expressions, exponents, power, symmetry, shapes study etc. Once you practice problems, this is easy to find solutions with a depth understanding of concepts.

When you study online, you can practice easy tricks to solve the most complicated problems. Also, everything is available at a single place with an explanation of diagrams and figures by expert teachers. You just have to select the topic for which you want to practice problems and start your work right away. This is the best way how can you prepare for exams to achieve maximum marks.

### Class 7 Maths Formulas by Chapters

Whenever you try to solve any complex problem, Math formulas can work best here to provide you with the appropriate answer. A formula is a wise technique to express the information related to a topic in terms of symbols. With the help of these formulas, you can find answers to tough problems during your exams. Also, teachers in school always advise you to learn formulas and not down separately in a notebook.

Just go through that particular book whenever you sit to solve a problem. Make sure that you have collected the 100 percent formulas to make your learning experience even better and suitable. We wish you all the very best for your exam preparation and score well in exams in 2018 and more years to come.