## Mensuration Formulas

We are going to share Mensuration Formulas for the student who is studying in the class of 5, 6, 7, 8, 9, 10, 11, and 12. In math, Mensuration is a very important topic which is helping to improve scores in the exam. If you want to become very intelligent in math then you should remember the Mensuration Formulas to resolve Mensuration related problems. If you have any questions related to the Mensuration please let me know through the comment and mail. There are millions of students looking for Mensuration formulas that why we shared the Mensuration formulas below.

### 2D Shapes Mensuration Formulas

 $\ Area\;of\;Square = l^{2}$ $\ Perimeter\;of\;Square = 4 \times l$Where, l : length of side $\ Area\;of\;Rectangle = l \times w$ $\ Perimeter\;of\;Rectangle = 2 (l+w)$Where, L = Length w = Width $\ Area\;of\;Circle = \pi r^{2}$ $\ Perimeter\;of\;Circle = 2 \pi r$Where, 𝒓 = Radius d = Diameter d = 2𝒓 $\ Area\;of\;Scalene\;Triangle = \sqrt{s(s-a)(s-b)(s-c)}$ $\ Perimeter\;of\;Scalene\;Triangle = a+b+c$Where, a, b, c are Side of Scalene Triangle $Area\;of\;Isoscele\;Triangle =\frac{1}{2}bh$ $Altitude\;of\;an\;Isosceles\;Triangle=\sqrt{a^{2}-\frac{b^{2}}{4}}$ Where, b = Base of the isosceles triangle h = Height of the isosceles triangle & a = length of the two equal sides $\large Perimeter\;of\;Isosceles\;Triangle,P=2\,a+b$ Where, a = length of the two equal sides b = Base of the isosceles triangle $Area \;of \;an \;Right\;Triangle = \frac{\sqrt{1}}{2}bh$ $Perimeter \;of \;an \;Right \;Triangle = a+b+c$ $semi\;Perimeter \;of \;an \;Right \;Triangle = \frac{a+b+c}{2}$ where, b is the Base of Right Triangle. h is the Hypotenuse of Right Triangle. a is the Hight of Right Triangle. $Area \;of \;an \;Equilateral \;Triangle = \frac{\sqrt{3}}{4}a^{2}$ $Perimeter \;of \;an \;Equilateral \;Triangle = 3a$ $Semi \;Perimeter \;of \;an \;Equilateral \;Triangle = \frac{3a}{2}$ $Height \;of \;an \;Equilateral \;Triangle = \frac{\sqrt{3}}{2}a$ Where, a is the side of an equilateral triangle. h is the altitude of an equilateral triangle. $\large perimeter\;of\;a\;rhombus =4\times Side$ $\large Area\;of\;a\;Rhombus = A = \frac{1}{2} \times d_{1} \times d_{2}$ Where, d1 and d2 are the diagonals of the rhombus bisect each other 90-degree angle. $\ Area\;of\;a\;Parallelogram = b\times h$ $\ Perimeter\;of\;Parallelogram = 2\left(b+h\right)$ Where, b: Base h: Height. $\large Perimeter\;of\;a\;Trapezoid\;=a+b+c+d$ Where, a, b, c, d are the lengths of each side. $\large Area\;of\;a\;Trapezoid\; = \frac{1}{2} \times h \times (a + b)$ Where:, h = height a = the short base b = the long base

### 3D Shapes Mensuration Formulas

 $\large Surface\;area\;of\;Cube=6a^{2}$ $\large Volume\;of\;a\;cube=a^{3}$ Where, a is the side length of the cube. $\large Surface\;area\;of\;Cuboid = 2(lb + bh + hl)$ $\large Volume\;of\;a\;Cuboid = h \times l \times w$ Where, l: Height h: Legth w: Depth $\large Diameter\;of\;a\;sphere=2r$ $\large Circumference\;of\;a\;sphere=2\pi r$ $\large Surface\;area\;of\;a\;sphere=4\pi r^{2}$ $\large Volume\;of\;a\;sphere=\frac{4}{3}\: \pi r^{3}$ Where, r: Radius $\large Curved\;Surface\;area\;of\;a\;Hemisphere =4\pi r^{2}$ $\large Total\;Surface\;area\;of\;a\;Hemisphere =3\pi r^{2}$ $\large Volume\;of\;a\;Hemisphere =\frac{2}{3}\: \pi r^{3}$ Where, r: Radius $\large Curved\;Surface\;area\;of\;a\;Cylinder =2\pi rh$ $\large Total\;Surface\;area\;of\;a\;Cylinder =2\pi r(r+h)$ $\large Volume\;of\;a\;Cylinder = \pi r^{2} h$ Where, r: Radius h: Height $\large Total\;Surface\;Area\;of\;cone=\pi r \left (s+r \right )$ $\large Vomule\;of\;cone=\frac {1}{3}\pi r^{2}h$ $\large Curved\;Surface\;Area\;of\;cone=\pi rs$ Where, r is the radius of cone. h is the height of cone. s is the slant height of the cone.

#### Check More 3D Shapes Mensuration Formulas

 Cube Formulas Hemisphere Formulas Cuboid Formulas Cylinder Formulas Sphere Formulas Cone Formulas